Unfortunately I find nothing in Asher's past or sheets to tell me different. Now the GM can clue me into stuff I've missed.

I'm developing a shopping list for the next time we are in port.

We should loot.. I mean check the supplies in the atmo station before we leave.
There may be some goodies in the security section.

Roger, if you can answer my PM questions, I'll get a post up tonight.

You'd think by now the crew would know better than to leave Asher unsupervised.

I didn't hear from Roger so my post is pretty weak. After I hear, I'll firm thing up or change direction.

Either way..let the chaos begin!

Sorry dude but I fell prey to sleep when i got home. Will go through your questions now.

I am putting up these answers for everyone, just in case.

What's the distance from Asher to the Marshall and the ASREV?

The two ships are 100 yards apart. The group has gathered more less half way between the two so you are 150 feet away not counting the diagonally as you are above them.
How good is Asher's pitching arm?

You have a d10 agility and d4 in ranged weapons but d6 in athletics. So your high is 14-16 which covers Formidable feats but not Heroic.
What the delay in seconds on a smoke grenade and other grenades?

I can not see anywhere in the rules so I will apply the holy hand grenade rule of 3 seconds.
WHAT?? I'm just asking?

Yeah, you are always just asking. That is why I love you as a player
Well wouldn't you look up if a smoke bomb went off about twenty feet over your head or off the ASREV control room portal?

You would not want me in an ASREV. However to answer your question, yes that would be a normal reaction. Depends how well trained the crew member and how often they have been fooled by a diversion.
Is Tess close enough to toss a EMP into the ARSEV and can Ash see her?

Ash can see her but she is following Matherson and his two thugs and is nowhere near enough to make the sprint to the other ship.

This is how I see the scene right now. Anyone disagree with their positioning, let me know. X are passengers.

This made me think of Asher so much. I had to post it.

Drools over gun!!!!

Alright then... 3 second fuse.....100 yards....3 feet per yard.....5280 feet in a mile.....80 mph pitch... 80 x 5820.. feet per hour..... divide by 3600 sec in an hour... feet per sec..... carry the... figure wind.... arc to tangent... newton's law...hmmm... spirals release.....add height of perch...... square of the hypot....hmmmm...angle of.......352 feet straight line in 3 seconds.....deduce for arc and drop....

Yep that'll be the right in front of the ASREV pilot!
-----------------
Almost missed: x^2 + 3x + 9 from 0 to 10 times 3/20 then - 59 e^(i ð) + 1 = 0

z = x + iy = |z| (\\cos \\phi + i\\sin \\phi ) = r e^{i \\phi} \\ \\bar{z} = x - iy = |z| (\\cos \\phi - i\\sin \\phi ) = r e^{-i \\phi} \\
where
x = \\mathrm{Re}\\{z\\} \\, the real party = \\mathrm{Im}\\{z\\} \\, the imaginary partr = |z| = \\sqrt{x^2+y^2} the magnitude of z\\phi = \\arg z = \\, atan2(y, x) .

Okay......better!

That almost convinced me.





Almost....

Another GM call.
What would be the standard scope power of an general issue GRZ 1?

Asher gun skills and fair scope gives him a good chance of clean hit. Beside that lady's skull won't slow the bullet that much.

A standard scope gives you +1 die rank in your skill.

BTW - Asher's "talent" is his handguns, nor rifles. Not to say he isn't good with them but your talent will not be incorporated.

Let's figure the shot now!

\\cos x\\cdot \\cos y & = \\frac{(e^{ix}+e^{-ix})}{2} \\cdot \\frac{(e^{iy}+e^{-iy})}{2} \\\\ & = \\frac{1}{2}\\cdot \\frac{e^{i(x+y)}+e^{i(x-y)}+e^{i(-x+y)}+e^{i(-x-y)}}{2} \\\\ & = \\frac{1}{2} \\bigg[ \\underbrace{ \\frac{e^{i(x+y)} + e^{-i(x+y)}}{2} }_{\\cos(x+y)} + \\underbrace{ \\frac{e^{i(x-y)} + e^{-i(x-y)}}{2} }_{\\cos(x-y)} \\bigg] \\ \\end{align}
allow for scope!
\\cos(nx) & = \\mathrm{Re} \\{\\ e^{inx}\\ \\} = \\mathrm{Re} \\{\\ e^{i(n-1)x}\\cdot e^{ix}\\ \\} \\\\ & = \\mathrm{Re} \\{\\ e^{i(n-1)x}\\cdot (e^{ix} + e^{-ix} - e^{-ix})\\ \\} \\\\ & = \\mathrm{Re} \\{\\ e^{i(n-1)x}\\cdot \\underbrace{(e^{ix} + e^{-ix})}_{2\\cos(x)} - e^{i(n-2)x}\\ \\} \\\\ & = \\cos[(n-1)x]\\cdot 2 \\cos(x) - \\cos[(n-2)x]


Hmmmm.......... it's close!

you want to throw a grenade down the full length of a football field. Try punting it instead.

You two are sooo cute almost like a married couple

And yes Ody the M-4 is very nice It replaced the M16A2 with a better rate of fire and a much better ballistic profile. I enjoyed shooting it very much at a recent gun show I went to, to buy more ammo for my FMK 9mm handgun. Going to a refresher handgun course next month and then 4 days later for my CHL license

I wouldn't count on Connor to play. He has shown about as much interest in this as he has shown in anything that requires he remove his nose from a book. Which is to say, very little at best. Sorry about that.